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[Frama-c-discuss] definition of \base_addr

  • Subject: [Frama-c-discuss] definition of \base_addr
  • From: jens.gerlach at first.fraunhofer.de (Jens Gerlach)
  • Date: Wed Nov 26 21:53:01 2008
Hi,

the definition of \base_addr reads "returns the base address of an  
allocated pointer".
I assume that for global or local variable a of type int a[4] holds:
	\base_addr(&a[3]) = \base_addr(a+3) = \base_addr(a)

But what if we define

struct X {
     int b[4];
};

X x[5];

What is then the value of
	\base_addr(&(x[2].b[1])) ?
Is it
	&(x[2].b[0]) ( which I think is equal to x+2)
or
	&(x[0].b[0]) (which I think is equal to x)
?

Thanks in advance.

Jens