# Frama-C-discuss mailing list archives

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# [Frama-c-discuss] hint assertions and understanding cooperation between wp and value plugin

```Hello,

>This setting (1094) seems a bit high for such a simple formula. Out of curiosity, what were the possible values
>for x?

I made this test for x âˆˆ [-1e6, 1e6]

#include <__fc_builtin.h>
int main()
{
double x =  Frama_C_double_interval(-1e6, +1e6);
double x0 = x*x;
/*@ assert x0 >= 0.; */
return 0;
}

frama-c -val t.c -val-subdivide-non-linear N

But I only checked the lower bound for x0 in the output of the value
plugin, it is -0 until N=1094

with N=1093:

[...]
x âˆˆ [-1000000. .. 1000000.]
x0 âˆˆ [-0. .. 1e+12]

N=1094:

[...]
x âˆˆ [-1000000. .. 1000000.]
x0 âˆˆ [0. .. 1e+12]

I did not look at the assertion... It becomes valid here for N=1 !

I just thought that if x0 is only printed as >= -0 in the output of
value analysis, it means that there is a possibility that it is >= a
small negative value that has been rounded to zero and then x0 >= 0 may
not hold, so it is not necessary to check the assertion.

>Again, this is a bit strange. I'm able to analyse the following program and prove that r >= -0. using
>-val-subdivide-non-linear 1080. You may obtain different results with different bounds for x, because the
>subdivision strategy depends on the initial interval. However, there should be no need to go to extreme values
>such as 99999.

I only try to see the disparition of the -0 bound with
the increase of N.

For:
double x0 = (x-0.1)*(x-0.1);

the -0 bound seems to never disappear (in fact the value plugin returns
quickly even if N is very high)

And the assertion becomes valid for N=75.

Maurice

```