Tag Archives: anonymous-arrays

Solution to yesterday's quiz
Pascal Cuoq on 29 November 2012

Yesterday's quiz was about the expression *(char*)(float[]){x*x} - 63 (for big-endian architectures) or *(3+(char*)(float[]){x*x}) - 63 (for little-endian ones). This post provides an explanation. First, let us try the function on a few values: int main(){ for (unsigned int i=0; i<=20; i++) printf(\l(%2u)=%d" i l(i)); } This may provide the...

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